Question:
The value of $\frac{1\times 2^2+2\times3^2+...+100\times (101)^2}{1^2 \times 2\times2^2 \times3+...+100^2 \times 101}$
The value of $\frac{1\times 2^2+2\times3^2+...+100\times (101)^2}{1^2 \times 2\times2^2 \times3+...+100^2 \times 101}$
Updated On: Sep 4, 2025
- 305/301
- 301/305
- 350/310
- 310/350
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The Correct Option is A
Solution and Explanation
The Correct answer is option(A) : 305/301
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