Question

The value of \(∫\frac{dx}{x^2-6x+13}\)is:

• A. \(\frac{1}{2} tan^{-1}\frac{x-3}{2}+C\), where C is constant of integration.
• B. \(\frac{1}{2} cot^{-1}\frac{x-3}{2}+C\), where C is constant of integration.
• C. \(\frac{1}{2} tan^{-1}\frac{x+3}{2}+C\), where C is constant of integration.
• D. \(\frac{1}{2} cot^{-1}\frac{x+3}{2}+C\), where C is constant of integration.

Answer 1

The Correct Option is A

The correct option is(A):\(\frac{1}{2} tan^{-1}\frac{x-3}{2}+C\), where C is constant of integration.