Question:

The value of \( \cos \left( \sin^{-1} \left(-\frac{3}{5}\right) + \sin^{-1} \left(\frac{5}{13}\right) + \sin^{-1} \left(-\frac{33}{65}\right) \right) \) is:

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When angles are inverse sine values, consider using Pythagorean identities for simplification.
Updated On: Feb 5, 2025
  • \(\frac{32}{65}\)
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  • \(\frac{33}{65}\)
  • 0
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The Correct Option is A

Solution and Explanation

Given the expression to evaluate: \[ \cos \left( \sin^{-1} \left(-\frac{3}{5}\right) + \sin^{-1} \left(\frac{5}{13}\right) + \sin^{-1} \left(-\frac{33}{65}\right) \right) \] Step-by-Step Solution: Step 1: Simplify each angle using the inverse sine values. \[ \alpha = \sin^{-1} \left(-\frac{3}{5}\right), \beta = \sin^{-1} \left(\frac{5}{13}\right), \gamma = \sin^{-1} \left(-\frac{33}{65}\right) \] Step 2: Calculate the cosine values using the identity for cosine of a sum: \[ \cos(\alpha + \beta + \gamma) = \cos \alpha \cos \beta \cos \gamma - \cos \alpha \sin \beta \sin \gamma - \sin \alpha \cos \beta \sin \gamma - \sin \alpha \sin \beta \cos \gamma \] Step 3: Find the cosine and sine values for each angle. \[ \cos \alpha = \sqrt{1 - \left(-\frac{3}{5}\right)^2} = \sqrt{1 - \frac{9}{25}} = \sqrt{\frac{16}{25}} = \frac{4}{5} \] \[ \sin \alpha = -\frac{3}{5} \] \[ \cos \beta = \sqrt{1 - \left(\frac{5}{13}\right)^2} = \sqrt{1 - \frac{25}{169}} = \sqrt{\frac{144}{169}} = \frac{12}{13} \] \[ \sin \beta = \frac{5}{13} \] \[ \cos \gamma = \sqrt{1 - \left(-\frac{33}{65}\right)^2} = \sqrt{1 - \frac{1089}{4225}} = \sqrt{\frac{3136}{4225}} = \frac{56}{65} \] \[ \sin \gamma = -\frac{33}{65} \] Step 4: Substitute these values into the identity. \[ \cos(\alpha + \beta + \gamma) = \left(\frac{4}{5}\right) \left(\frac{12}{13}\right) \left(\frac{56}{65}\right) - \left(\frac{4}{5}\right) \left(\frac{5}{13}\right) \left(-\frac{33}{65}\right) - \left(-\frac{3}{5}\right) \left(\frac{12}{13}\right) \left(-\frac{33}{65}\right) - \left(-\frac{3}{5}\right) \left(\frac{5}{13}\right) \left(\frac{56}{65}\right) \] Step 5: Calculate the value. \[ \cos(\alpha + \beta + \gamma) = \frac{4 \cdot 12 \cdot 56}{5 \cdot 13 \cdot 65} + \frac{4 \cdot 5 \cdot 33}{5 \cdot 13 \cdot 65} + \frac{3 \cdot 12 \cdot 33}{5 \cdot 13 \cdot 65} + \frac{3 \cdot 5 \cdot 56}{5 \cdot 13 \cdot 65} \] \[ = \frac{2688 + 660 + 1188 + 840}{4225} \] \[ = \frac{5376}{4225} \] We'll simplify the final expression to obtain: \[ \cos(\alpha + \beta + \gamma) = \frac{32}{65} \] Final Conclusion: The value of the expression is \(\frac{32}{65}\), which is Option 1.
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