Question:
The value of $∫_0^{\frac{\pi}{4}} \frac{dx}{1+tanx} $
The value of $∫_0^{\frac{\pi}{4}} \frac{dx}{1+tanx} $
Updated On: Jan 15, 2025
- $\frac{π}8 + In 2$
- $\frac{π}4 + In 2$
- $\frac{π}8 +\frac{1}2 In 2$
- $\frac{π}8 +\frac{1}4 In 2$
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The Correct Option is D
Solution and Explanation
The Correct answer is option is (D) : $\frac{π}8 +\frac{1}4 In 2$
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