Question:
The value of \(\displaystyle\int_{0}^{\sqrt3}\frac{6}{9+x^2}dx\) is equal to
The value of \(\displaystyle\int_{0}^{\sqrt3}\frac{6}{9+x^2}dx\) is equal to
Updated On: Jun 10, 2024
- \(\frac{\pi}{3}\)
- \(\frac{\pi}{6}\)
- \(\frac{\pi}{4}\)
- \(\frac{2\pi}{3}\)
- 1
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{\pi}{3}\)
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