The two light beams having intensities $I$ and $9I$ interfere to produce a fringe pattern on a screen. The phase difference between the beams is $\frac {\pi}{2}$ at point P and $\pi$ at point Q. Then the difference between the resultant intensities at P and Q will be:

Question

The two light beams having intensities  $I$  and  $9I$  interfere to produce a fringe pattern on a screen. The phase difference between the beams is  $\frac {\pi}{2}$  at point P and  $\pi$  at point Q. Then the difference between the resultant intensities at P and Q will be:

cdquestions Admin · Accepted Answer

$IP = I+9I+2\sqrt {I\times9I} \ cos \frac {\pi}{2}= 10I$ $IP = I+9I+2\sqrt {I\times9I} \ cos \pi= 14I$ Then, the difference between the resultant intensities $I_P - I_Q = 6I$ Hence, the correct option is (B):  $6I$

Answer

$2I$

Answer

$6I$

Answer

$5I$

Answer

$7I$

The two light beams having intensities \(I\) and \(9I\) interfere to produce a fringe pattern on a screen. The phase difference between the beams is \(\frac {\pi}{2}\) at point P and \(\pi\) at point Q. Then the difference between the resultant intensities at P and Q will be:

The Correct Option is B

Solution and Explanation

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