Question:

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m, and 120 m (see figure below). The advertisements yield an earning of ₹ 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?
triangular side walls of a flyover

Updated On: Nov 16, 2023
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Solution and Explanation

The sides of the triangle (i.e., a, b, c) are of 122 m, 22 m, and 120 m respectively.
Perimeter of triangle = (122 + 22 + 120) m 
2s = 264 m 
s = 132 m
By Heron's formula
Area of a triangle =s(s - a)(s - b)(s - c) \sqrt{\text{s(s - a)(s - b)(s - c)}}

132(132 - 122) (132 - 22) (132 - 120)\sqrt{\text{132(132 - 122) (132 - 22) (132 - 120)}}

=132 × 10 × 110 × 12= \sqrt{\text{132 × 10 × 110 × 12}}

= 1320 m2

Rent of 1 m2 area per year = ₹ 5000

Rent of 1 m2 area per month = 500012₹ \frac{5000}{12}

Rent of 1320 marea for 3 months = (500012\frac{5000}{12}) × 3 × 1320

1650000
Therefore, the company paid ₹ 16,50,000 as rent.

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