Question:

The total number of ways the word 'DAUGHTER' can be arranged so that all vowels don't occur together:

Show Hint

When arranging words with restrictions, first calculate the number of ways to arrange the consonants and then the number of ways to arrange the vowels in available positions.
Updated On: Jan 26, 2025
  • 36000
  • 37000
  • 35000
  • 38000
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The word "DAUGHTER" has 8 letters, with 3 vowels (A, U, E) and 5 consonants (D, G, H, T, R). To arrange the letters so that the vowels don't occur together: - First, arrange the 5 consonants: \( 5! = 120 \) ways. - Now, place the 3 vowels in the 6 available positions (before the first consonant, between consonants, and after the last consonant). The number of ways to choose 3 positions from 6 is \( \binom{6}{3} = 20 \). - The 3 vowels can be arranged in these positions in \( 3! = 6 \) ways. Thus, the total number of arrangements is \( 5! \times \binom{6}{3} \times 3! = 120 \times 20 \times 6 = 36000 \). Thus, the correct answer is option (1).
Was this answer helpful?
0
1