To determine the total number of sigma (\(\sigma\)) and pi (\(\pi\)) bonds in 2-oxohex-4-ynoic acid, analyze the structure:
\[\text{HO-CH}_2 - \text{C(=O)} - \text{CH}_2 - \text{C} \equiv \text{C} - \text{CH}_3\]
Count the sigma bonds (\(\sigma\)-bonds):
\(6 \, \sigma\)-bonds in carbon-hydrogen (C-H) bonds.
\(5 \, \sigma\)-bonds in carbon-carbon (C-C) single bonds.
\(2 \, \sigma\)-bonds in carbon-oxygen (C=O and C-O) bonds.
\(1 \, \sigma\)-bond in the hydroxyl (O-H) group.
Total \(\sigma\)-bonds: \(6 + 5 + 2 + 1 = 14\)
Count the pi bonds (\(\pi\)-bonds):
\(1 \, \pi\)-bond in the C=O bond.
\(3 \, \pi\)-bonds in the C \(\equiv\) C triple bond (\(2 \, \pi\)-bonds in the triple bond).
Total \(\pi\)-bonds: \(1 + 3 = 4\)
Therefore, the total number of bonds (sigma and pi) is:
\[14 + 4 = 18\]