To determine the total number of sigma (\(\sigma\)) and pi (\(\pi\)) bonds in 2-oxohex-4-ynoic acid, analyze the structure:
\[\text{HO-CH}_2 - \text{C(=O)} - \text{CH}_2 - \text{C} \equiv \text{C} - \text{CH}_3\]
Count the sigma bonds (\(\sigma\)-bonds):
\(6 \, \sigma\)-bonds in carbon-hydrogen (C-H) bonds.
\(5 \, \sigma\)-bonds in carbon-carbon (C-C) single bonds.
\(2 \, \sigma\)-bonds in carbon-oxygen (C=O and C-O) bonds.
\(1 \, \sigma\)-bond in the hydroxyl (O-H) group.
Total \(\sigma\)-bonds: \(6 + 5 + 2 + 1 = 14\)
Count the pi bonds (\(\pi\)-bonds):
\(1 \, \pi\)-bond in the C=O bond.
\(3 \, \pi\)-bonds in the C \(\equiv\) C triple bond (\(2 \, \pi\)-bonds in the triple bond).
Total \(\pi\)-bonds: \(1 + 3 = 4\)
Therefore, the total number of bonds (sigma and pi) is:
\[14 + 4 = 18\]
Match the LIST-I with LIST-II:
Choose the correct answer from the options given below :
The number of molecules/ions that show linear geometry among the following is _____. SO₂, BeCl₂, CO₂, N₃⁻, NO₂, F₂O, XeF₂, NO₂⁺, I₃⁻, O₃
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32