Question

The time taken for 5% of a drug to decompose by first-order kinetics is:

• A. \( 0.022/k_1 \)
• B. \( 0.051/k_1 \)
• C. \( 0.105/k_1 \)
• D. \( k_1/0.051 \)

Hint:

First-order kinetics applies to most drug degradation processes, aiding shelf-life determinations.

Answer 1

The Correct Option is B

First-order kinetics follows: \[ t = \frac{\ln (1/f)}{k} \] For 5% decomposition, \( f = 0.95 \), yielding: \[ t = \frac{\ln (1/0.95)}{k} = \frac{0.051}{k} \] This equation governs drug degradation and stability predictions.