The color code for resistors is as follows:
Red = 2
Black = 0
Orange = \( \times 10^3 \)
So, the resistor value is: \[ (2 \times 10 + 0) \times 10^3 = 20 \times 10^3 = 20000 \, \Omega \] Since the fourth color (which indicates the tolerance) is absent, we assume a tolerance of ±20% for carbon resistors. The tolerance is calculated as: \[ \text{Tolerance} = 20\% \times 20000 = 4000 \, \Omega \]
Thus, the correct answer is (D): \( \pm 4000 \, \Omega \).
The colour code for a carbon resistor uses 4 bands:
1st Band (Red): 2
2nd Band (Black): 0
3rd Band (Orange - multiplier): \( 10^3 \)
So, the resistance value is:
\( R = 20 \times 10^3 = 20000\,\Omega = 20\,k\Omega \)
4th Band (Tolerance):
Since the fourth band is absent, the tolerance is assumed to be:
\( \pm 20\% \)
Tolerance value = \( 20\% \) of \( 20000\,\Omega \) = \( 0.2 \times 20000 = 4000\,\Omega \)
Final Answer: \( \boxed{\pm 4000\,\Omega} \)

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \[ (R_1=R_2=R_3=R_4). \] When \(R_3\) resistance is heated, its resistance value increases by \(10%\). The potential difference \((V_a-V_b)\) after \(R_3\) is heated is _______ V. 