Question

The sum of roots of the quadratic equation \(3x^2-6x+1=0\) is

• A. 2
• B. \(3 \pm \sqrt{6}\)
• C. -3
• D. \(\frac{1}{3}\)

Answer 1

The Correct Option is A

Step 1: Recall the standard form of a quadratic equation

The general form is: \( ax^2 + bx + c = 0 \)

Step 2: Identify coefficients from the given equation

Given: \( 3x^2 - 6x + 1 = 0 \)
Here, \( a = 3 \), \( b = -6 \), \( c = 1 \)

Step 3: Use the formula for sum of roots

Sum of roots of a quadratic equation is given by:
\( \text{Sum} = -\frac{b}{a} \)

Step 4: Substitute the values of \( b \) and \( a \)

\( \text{Sum} = -\frac{-6}{3} = \frac{6}{3} = 2 \)

Correct Option: (A): 2