$CH_3-CH(CH_3)-MgBr $
$ CH_3-CH_2-CH_2MgBr$
To prepare 2-methylpropan-1-ol using methanal and a Grignard reagent, we follow this reaction:
\( \text{HCHO} + \text{R–MgBr} \xrightarrow{\text{ether}} \text{R–CH}_2\text{OH} \)
The required product is 2-methylpropan-1-ol, which has the structure:
\( \text{CH}_3–\text{CH(CH}_3)–\text{CH}_2\text{OH} \)
This shows that the R group in the Grignard reagent should be isopropyl \( (\text{CH}_3–\text{CH(CH}_3)–) \).
So, the correct Grignard reagent is:
\( \text{CH}_3–\text{CH(CH}_3)–\text{MgBr} \)
Option (A): \( \text{CH}_3–\text{CH(CH}_3)–\text{MgBr} \)
The CORRECT statement(s) for the given reactions is(are):