The CORRECT statement(s) for the given reactions is(are):
Let's analyze the reactions one by one:
- Reaction I: The reaction involves an aldehyde (MeCHO) and MeMgBr (Grignard reagent). Grignard reagents add to the carbonyl group of aldehydes to form a secondary alcohol, which on hydrolysis with \( H_3O^+ \) will yield product P (\( {MeCH(OH)Me} \)). Therefore, the major product in reaction I is P.
Thus, the correct match for reaction I is \( A \).
- Reaction II: In this case, a Grignard reagent (PrMgBr) is added to the aldehyde (MeCHO). The product formed is again a secondary alcohol, which is product P (\( {MeCH(OH)Me} \)). Therefore, the major product in reaction II is also P.
Thus, the correct match for reaction II is \( B \).
- Reaction III: Here, the reaction involves excess MeMgBr with an ester (MeCOOCH₃). Excess Grignard reagent will attack the ester to form a tertiary alcohol, which corresponds to product Q (\( {MeCOOMe} \)).
Thus, the correct match for reaction III is \( C \).
Thus, the correct answer is option (A), (B), (C).
The Maximum number of RBr producing 2-methylbutane by above sequence of reaction