Question:

The CORRECT statement(s) for the given reactions is(are):

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Grignard reagents add to carbonyl compounds (such as aldehydes and esters) to form alcohols. The excess reagent can lead to the formation of tertiary alcohols in the case of esters.
Updated On: May 5, 2025
  • P is formed as the major product in reaction I.
  • P is formed as the major product in reaction II.
  • Q is formed as the major product in reaction IV.
  • R is formed as the major product in reaction III.
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The Correct Option is A, B, C

Solution and Explanation

Let's analyze the reactions one by one: 
- Reaction I: The reaction involves an aldehyde (MeCHO) and MeMgBr (Grignard reagent). Grignard reagents add to the carbonyl group of aldehydes to form a secondary alcohol, which on hydrolysis with \( H_3O^+ \) will yield product P (\( {MeCH(OH)Me} \)). Therefore, the major product in reaction I is P. 
Thus, the correct match for reaction I is \( A \).
- Reaction II: In this case, a Grignard reagent (PrMgBr) is added to the aldehyde (MeCHO). The product formed is again a secondary alcohol, which is product P (\( {MeCH(OH)Me} \)). Therefore, the major product in reaction II is also P. 
Thus, the correct match for reaction II is \( B \).
- Reaction III: Here, the reaction involves excess MeMgBr with an ester (MeCOOCH₃). Excess Grignard reagent will attack the ester to form a tertiary alcohol, which corresponds to product Q (\( {MeCOOMe} \)).
Thus, the correct match for reaction III is \( C \).
Thus, the correct answer is option (A), (B), (C).

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