The correct answer is 35
\(\frac{hc}{λ} - Ø = KE = eV_0 \)
\(⇒ \frac{6.63 × 10^{-34} × 3 × 10^8}{6630 × 10^{-10}} - 6.63 × 10^{-34}\)
\(= ƒ_{th} = 1.6 × 10^{-19} × 0.4\)
\(⇒ ƒ_{th} ≃35.11 × 10^{13} H\)
Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).
The magnitude of heat exchanged by a system for the given cyclic process ABC (as shown in the figure) is (in SI units):
