The Statue of Unity situated in Gujarat is the world’s largest Statue which stands over a 58 m high base. As part of a project, a student constructed an inclinometer and wishes to find the height of the Statue of Unity using it. He noted the following observations from two places:
Situation – I: The angle of elevation of the top of Statue from Place A, which is $80\sqrt{3}$ m away from the base of the Statue, is found to be $60^\circ$.
Situation – II: The angle of elevation of the top of the Statue from a Place B, which is 40 m above the ground, is found to be $30^\circ$ and the total height of the statue including the base is given to be 240 m.
Based on the given information, answer the following:
Let the total height of the statue (including base) be $h + 58$ m.
Let point A be at a distance $AB = 80\sqrt{3}$ m from the base of the statue.
Let point C be the top of the statue, and B be the base of the statue.
Then in $\triangle ABC$, $\angle CAB = 60^\circ$, $AB = 80\sqrt{3}$, and $BC = h + 58$.
We can represent this scenario with a right triangle diagram:
In this case: - The total height of the Statue (including base) is 240 m. - The observer is standing at a height of 40 m above the ground. - The angle of elevation to the top of the Statue from this point is $30^\circ$. Let: - $C$ be the top of the Statue - $B$ be the base of the Statue - $D$ be the observation point 40 m above the ground - $CD = 240 - 40 = 200$ m - $AD$ be the horizontal distance from point D to the Statue This forms a right triangle $\triangle DCA$ with: \[ \angle D = 30^\circ,\quad \text{opposite side } = 200\text{ m} \]
The given graph illustrates:
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There is a circular park of diameter 65 m as shown in the following figure, where AB is a diameter. An entry gate is to be constructed at a point P on the boundary of the park such that distance of P from A is 35 m more than the distance of P from B. Find distance of point P from A and B respectively.