Question

The 'Spin only' Magnetic moment for \([Ni(NH_3​)_6​]^{2+}\) is _____ × \(10^{−1}\) BM. (given = Atomic number of Ni : 28)

Answer 1

Correct Answer: 28

NH$_3$ acts as a weak field ligand with Ni$^{2+}$.
\[ \text{Ni}^{2+} = 3d^8 \]

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\[ \text{No. of unpaired electrons} = 2 \]
\[ \mu = \sqrt{n(n+2)} = \sqrt{8} = 2.82 \, \text{BM} \]
\[ 28.2 \times 10^{-1} \, \text{BM} \]
\[ x = 28 \]