Disproportionation reactions involve a species being simultaneously oxidized and reduced to form two different products. Among the given species:
- \( \text{ClO}_2^- \) and \( \text{ClO}_3^- \) can undergo disproportionation to form \( \text{ClO}_3^- \) and \( \text{ClO}_2 \), respectively.
- \( \text{ClO}_4^- \) does not undergo disproportionation because it is already in its most oxidized state as a chlorine(V) species, and there is no higher oxidation state to form.
Thus, the correct answer is \( \text{ClO}_4^- \), which does not undergo disproportionation.