Question:
The sine of the angle between the straight line \(\frac{x-2}{3}=\frac{3-y}{-4}=\frac{z-4}{5}\) and the plane 2x - 2y + z = 5 is
The sine of the angle between the straight line \(\frac{x-2}{3}=\frac{3-y}{-4}=\frac{z-4}{5}\) and the plane 2x - 2y + z = 5 is
Updated On: Apr 9, 2024
- \(\frac{3}{\sqrt{50}}\)
- \(\frac{3}{50}\)
- \(\frac{4}{5\sqrt2}\)
- \(\frac{\sqrt2}{10}\)
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The Correct Option is D
Solution and Explanation
The correct answer is (D) : \(\frac{\sqrt2}{10}\).
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