Question

The SI unit of \( \frac{G}{g} \) is ( \( g \) = acceleration due to gravity, \( G \) = constant of gravitation)

• A. \( \frac{\text{kg}}{\text{m}^2} \)
• B. \( \frac{\text{m}^2}{\text{kg}} \)
• C. \( \frac{\text{m}}{\text{kg}} \)
• D. \( \frac{\text{kg}}{\text{m}} \)

Hint:

To find the units of a formula, make sure to carefully divide the units of the numerator and denominator.

Answer 1

The Correct Option is B

Step 1: Understanding the formula.
The gravitational constant \( G \) has units of \( \frac{\text{m}^3}{\text{kg} \cdot \text{s}^2} \) and acceleration due to gravity \( g \) has units of \( \text{m/s}^2 \). Thus, the units of \( \frac{G}{g} \) are: \[ \frac{\frac{\text{m}^3}{\text{kg} \cdot \text{s}^2}}{\text{m/s}^2} = \frac{\text{m}^2}{\text{kg}} \] Step 2: Conclusion.
The correct answer is (B), \( \frac{\text{m}^2}{\text{kg}} \).