Question:
The shortest distance of the point \((\frac{1}{2},1)\) from the curve \(y = |x -1| + |x + 1|\) is
The shortest distance of the point \((\frac{1}{2},1)\) from the curve \(y = |x -1| + |x + 1|\) is
Updated On: Sep 26, 2024
- 1
- 0
- \(\sqrt{2}\)
- \(\sqrt{\frac{3}{2}}\)
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The Correct Option is A
Solution and Explanation
The above illustration depicts the graph of \(y=∣x−1∣+∣x+1∣.\)
The shortest distance of \((\frac{1}{2},1)\)from the graph is 1
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