Comprehension
Gurveer and Arushi built a robot that can paint a path as it moves on a graph paper. Some co-ordinate of points are marked on it. It starts from graph paper. Some co-ordinate of points are marked on it. It starts from (0, 0), moves to the points listed in order (in straight lines) and ends at (0, 0).
Gurveer and Arushi built a robot that can paint
Question: 1

Determine the distance OP.

Updated On: June 02, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Given points:
\(O = (0, 0)\), \(P = (8, 6)\)

Step 1: Use distance formula between two points
\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Here,
\[ x_1 = 0, \quad y_1 = 0, \quad x_2 = 8, \quad y_2 = 6 \]

Step 2: Calculate distance \(OP\)
\[ OP = \sqrt{(8 - 0)^2 + (6 - 0)^2} = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10 \]

Final Answer:
\[ \boxed{10} \]
Was this answer helpful?
0
0
Question: 2

QS is represented by equation \(2x + 9y = 42\). Find the co-ordinates of the point where it intersects y-axis.

Updated On: June 02, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Given:
Equation of line \(QS\):
\[ 2x + 9y = 42 \]

Step 1: Find the coordinates where the line intersects the y-axis
At y-axis, \(x = 0\). Substitute \(x = 0\) into the equation:
\[ 2(0) + 9y = 42 \implies 9y = 42 \implies y = \frac{42}{9} = \frac{14}{3} \]

Final Answer:
The line \(QS\) intersects the y-axis at:
\[ \boxed{\left(0, \frac{14}{3}\right)} \]
Was this answer helpful?
0
0
Question: 3

Point R(4.8, y) divides the line segment OP in a certain ratio, find the ratio. Hence, find the value of y.

Updated On: June 02, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Given:
- Points \(O = (0,0)\) and \(P = (8,6)\)
- Point \(R = (4.8, y)\) divides the line segment \(OP\) in some ratio \(k : 1\)

Step 1: Use section formula
If point \(R\) divides segment \(OP\) in ratio \(k : 1\), coordinates of \(R\) are:
\[ \left( \frac{k \times x_2 + 1 \times x_1}{k + 1}, \frac{k \times y_2 + 1 \times y_1}{k + 1} \right) \] Where \(O = (x_1, y_1) = (0,0)\) and \(P = (x_2, y_2) = (8,6)\).

Step 2: Set x-coordinate equal to 4.8 and solve for \(k\)
\[ 4.8 = \frac{8k + 0}{k + 1} = \frac{8k}{k + 1} \] Multiply both sides by \(k + 1\):
\[ 4.8(k + 1) = 8k \implies 4.8k + 4.8 = 8k \] \[ 8k - 4.8k = 4.8 \implies 3.2k = 4.8 \implies k = \frac{4.8}{3.2} = 1.5 \]

Step 3: Find \(y\) using \(k = 1.5\)
\[ y = \frac{6k + 0}{k + 1} = \frac{6 \times 1.5}{1.5 + 1} = \frac{9}{2.5} = 3.6 \]

Final Answer:
- The ratio in which \(R\) divides \(OP\) is \(1.5 : 1\) or \(\frac{3}{2} : 1\).
- The value of \(y = 3.6\).

\[ \boxed{ \text{Ratio} = \frac{3}{2} : 1, \quad y = 3.6 } \]
Was this answer helpful?
0
0
Question: 4

Using distance formula, show that \(\frac{PQ}{OS} = \frac{2}{3}\).

Updated On: June 02, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Given:
Points \(P\), \(Q\), \(O\), and \(S\) with coordinates:
- \(P = (8, 6)\)
- \(Q = (12, 2)\)
- \(O = (0, 0)\)
- \(S = (-6, 6)\)

Step 1: Calculate distance \(PQ\) using distance formula
\[ PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(12 - 8)^2 + (2 - 6)^2} = \sqrt{4^2 + (-4)^2} = \sqrt{16 + 16} = \sqrt{32} = 4 \sqrt{2} \]

Step 2: Calculate distance \(OS\) using distance formula
\[ OS = \sqrt{(-6 - 0)^2 + (6 - 0)^2} = \sqrt{(-6)^2 + 6^2} = \sqrt{36 + 36} = \sqrt{72} = 6 \sqrt{2} \]

Step 3: Calculate the ratio \(\frac{PQ}{OS}\)
\[ \frac{PQ}{OS} = \frac{4 \sqrt{2}}{6 \sqrt{2}} = \frac{4}{6} = \frac{2}{3} \]

Final Answer:
\[ \boxed{\frac{PQ}{OS} = \frac{2}{3}} \]
Was this answer helpful?
0
0

Questions Asked in CBSE X exam

View More Questions

CBSE X Notification