Question:

The shaded region, where P=(1,0),Q=(1+2,2)R=(1+2,2),S=(1,0)P = (-1,0), Q = (-1 + \sqrt 2,\sqrt 2 )R = (-1 + \sqrt 2,-\sqrt 2), S = (1,0) is represented by

Updated On: Jun 14, 2022
  • | z + 1| >2,| arg (z + 1) |
  • | z + 1| < 2,| arg (z + 1) |
  • | z + 1| >2,| arg (z + 1) |>π4\frac{\pi}{4}
  • | z - 1| < 2,| arg (z + 1) |>π2\frac{\pi}{2}
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The Correct Option is A

Solution and Explanation

Since, | PQ | = | PS | = | PR | = 2
   \therefore \, \, \, Shaded part represents the external part of circle
having centre (-1,0) and radius 2.
As we know equation of circle having centre z0_0 and
radius r, is | z - z0z_0| = r
    z+1>2\Rightarrow \, \, \, \, |z+1|>2
Also, argument of z + 1 with respect to positive direction
of X-axis is π/4\pi/4
$\therefore \, \, \, \, \, \, \, arg(z+1) \le \frac{\pi}{4} \hspace25mm $..(i)
and argument of z + 1 in anticlockwise direction is π/4-\pi /4
$\therefore \, \, \, \, \, \, \, \, -\pi/4 \le \, arg (z + 1) \hspace25mm$...(ii)
From Eqs. (i) and (ii),
|arg (2 + 1) | π/4\le \pi/4
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.