Question:

The shaded region, where $P = (-1,0), Q = (-1 + \sqrt 2,\sqrt 2 )R = (-1 + \sqrt 2,-\sqrt 2), S = (1,0)$ is represented by

Updated On: Jun 14, 2022
  • | z + 1| >2,| arg (z + 1) |
  • | z + 1| < 2,| arg (z + 1) |
  • | z + 1| >2,| arg (z + 1) |>$\frac{\pi}{4}$
  • | z - 1| < 2,| arg (z + 1) |>$\frac{\pi}{2}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Since, | PQ | = | PS | = | PR | = 2
$\therefore \, \, \, $ Shaded part represents the external part of circle
having centre (-1,0) and radius 2.
As we know equation of circle having centre z$_0$ and
radius r, is | z - $z_0$| = r
$\Rightarrow \, \, \, \, |z+1|>2$
Also, argument of z + 1 with respect to positive direction
of X-axis is $\pi/4$
$\therefore \, \, \, \, \, \, \, arg(z+1) \le \frac{\pi}{4} \hspace25mm $..(i)
and argument of z + 1 in anticlockwise direction is $-\pi /4$
$\therefore \, \, \, \, \, \, \, \, -\pi/4 \le \, arg (z + 1) \hspace25mm$...(ii)
From Eqs. (i) and (ii),
|arg (2 + 1) | $\le \pi/4$
Was this answer helpful?
0
0

Questions Asked in JEE Advanced exam

View More Questions

Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.