Circle
Parabola
Ellipse
Hyperbola
pair of straight lines
The set of points of the form\((t^2 + t + 1, t^2 - t + 1)\),
where \(t\) is a real number, represents a parabola.
Let's analyze the given parametric equations:
\(x = t^2 + t + 1.y = t^2 - t + 1\)
These are parametric equations for the \(x\) and \(y\) coordinates of a point on the plane, where \(t\) is the parameter.
We can eliminate the parameter \(t\) to
Now can express \(y\) in terms of \(x\), (which will help us identify the geometric shape of the curve.)
Hence we get:
\(x - y = (t^2 + t + 1) - (t^2 - t + 1)\)
\(⇒ 2t x + y = (t^2 + t + 1) + (t^2 - t + 1)\)
\(= 2t^2 + 2\)
Now, solving for t in terms of x
\(t = \dfrac{x - y}{2}\)
Substitute the expression for \(t\) into \(x + y: x + y = 2(\dfrac{x - y}{2})^2 + 2\)
⇒ \(x + y =\dfrac{(x - y)^2}{2} + 2\)
⇒\((x - y)^2 =2x +2y - 4\)
Now, we have an equation that relates x and y without any parameter t. The equation is a second-degree equation, which represents a parabola.
the vertex of the parabola represented by the equation\((x - y)^2 = 2x + 2y - 4\) is at the point .\((1/2, 1/2).\)
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively:
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).
=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2