Question:

The set of all \( x \) for which \( \sin x \leq x \) is:

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Comparing Functions Graphically}
Remember standard inequality: \( \sin x<x \) for \( x>0 \)
Use test values: plug in \( x = 0.5, \frac{\pi}{4}, 1 \), etc.
Graphical understanding of concavity can help in verifying inequalities
Updated On: May 19, 2025
  • \( \left(0, \frac{\pi}{2}\right) \)
  • \( \left(\frac{\pi}{2}, \pi\right) \)
  • \( \left(-\frac{\pi}{2}, 0\right) \)
  • \( \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \)
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The Correct Option is A

Solution and Explanation

Consider the function \( f(x) = \sin x - x \). We analyze: - \( f(x)<0 \Rightarrow \sin x<x \Rightarrow \sin x \leq x \) - This inequality holds true in \( (0, \frac{\pi}{2}) \), as: - \( \sin x<x \) for all \( x>0 \) - \( \sin x>x \) for small negative \( x \) Hence, the valid region is: \[ \boxed{(0, \frac{\pi}{2})} \]
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