The resistance of a conductivity cell filled with 0.02 M KCl solution is 520 ohm at 298 K. The conductivity of the solution at 298 K is (Cell constant = 130 cm\(^{-1}\)):
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- \(0.50 \, {S cm}^{-1}\)
- \(1.25 \, {S cm}^{-1}\)
- \(0.025 \, {S cm}^{-1}\)
- \(0.25 \, {S cm}^{-1}\)
- \(0.75 \, {S cm}^{-1}\)
The Correct Option is D
Solution and Explanation
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