The reaction involves the formation of MeMgBr, with \( x \) and \( y \) representing the moles of MeMgBr and H, respectively.
From the reaction:
\[
\text{H} + \text{MeMgBr} \rightarrow \text{MeMgBr} + \text{OH}^-
\]
For the given quantities:
- \( x = 2 \) moles of MeMgBr
- \( y = 1 \) mole of H
Thus, the ratio of \( x/y \) is:
\[
x/y = 2/1 = 2
\]
The correct answer is (2).
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