For monatomic gases, the degrees of freedom are 3 (translational degrees of freedom). For diatomic gases, there are 5 degrees of freedom (3 translational + 2 rotational degrees of freedom). Thus, the ratio of the degrees of freedom for monatomic to diatomic gas molecules is: \[ \frac{3}{5} \] Therefore, the correct answer is 3:5 .
Observe the following data given in the table. (\(K_H\) = Henry's law constant)
| Gas | CO₂ | Ar | HCHO | CH₄ |
|---|---|---|---|---|
| \(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
For a first order decomposition of a certain reaction, rate constant is given by the equation
\(\log k(s⁻¹) = 7.14 - \frac{1 \times 10^4 K}{T}\). The activation energy of the reaction (in kJ mol⁻¹) is (\(R = 8.3 J K⁻¹ mol⁻¹\))
Note: The provided value for R is 8.3. We will use the more precise value R=8.314 J K⁻¹ mol⁻¹ for accuracy, as is standard.