The rate law for the decomposition of hydrogen iodide is - = d[HI]/dt = k[HI]2. The units of rate constant k are:
L mol-1 s-1
L-1 mol s-1
L2 mol-2 s-1
L1/2 mol1/2 s-1
To solve the problem, we need to determine the units of the rate constant \(k\) for the given rate law:
Given:
Rate law: \( \frac{-d[HI]}{dt} = k[HI]^2 \)
This is a second-order reaction because the exponent on the concentration term is 2.
1. General Unit Formula for Rate Constant:
For a reaction of order \(n\), the units of the rate constant \(k\) are:
\[
\text{Units of } k = \frac{\text{mol L}^{-1} \cdot \text{s}^{-1}}{(\text{mol L}^{-1})^n} = \text{mol}^{1-n} \cdot \text{L}^{n-1} \cdot \text{s}^{-1}
\]
2. Apply for Second-Order Reaction:
Here, \(n = 2\):
\[
\text{Units of } k = \text{mol}^{1-2} \cdot \text{L}^{2-1} \cdot \text{s}^{-1} = \text{mol}^{-1} \cdot \text{L} \cdot \text{s}^{-1}
\]
Final Answer:
The correct units of \(k\) are L mol−1 s−1.
The rate of a reaction:
A + B −→ product
is given below as a function of different initial concentrations of A and B.
Experiment | \([A]\) (mol L\(^{-1}\)) | \([B]\) (mol L\(^{-1}\)) | Initial Rate (mol L\(^{-1}\) min\(^{-1}\)) |
---|---|---|---|
1 | 0.01 | 0.01 | \(5 \times 10^{-3}\) |
2 | 0.02 | 0.01 | \(1 \times 10^{-2}\) |
3 | 0.01 | 0.02 | \(5 \times 10^{-3}\) |
Match the following:
Chemical kinetics is the description of the rate of a chemical reaction. This is the rate at which the reactants are transformed into products. This may take place by abiotic or by biological systems, such as microbial metabolism.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time. To be more specific, it can be expressed in terms of: (i) the rate of decrease in the concentration of any one of the reactants, or (ii) the rate of increase in concentration of any one of the products. Consider a hypothetical reaction, assuming that the volume of the system remains constant. R → P
Read More: Chemical Kinetics MCQ