Question:

The random variable X has a probability distribution P(X) of the following form, where k is some number.
\[P(X=x) \begin{cases} k & \quad \text{if } x=0\\ 2k & \quad \text{if } \text{ x=1}\\ 3k & \quad \text{if } \text{ x=2} \\ 0 & \quad \text{otherwise} \end{cases}\]
Then P(x≤2) is:

Updated On: May 21, 2024

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The Correct Option is B

The correct option is (B):1

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X	3	4	5
P(X)	0.5	0.2	0.3

X	0	1	2	3	4	5	6	7
P(X)	0	m	2m	2m	3m	m²	2m²	7m² + m

X	1	2	3	4	5	6	7
P(X)	k	2k	2k	3k	k²	2k²	7k² + k

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X	0	1	2	otherwise
P(X)	k	2k	3k	0

X	0	1	2	otherwise
P(X)	k	2k	3k	0