The products A and B obtained in the following reactions, respectively, are
3ROH+PCI3→3RCI+A
ROH+PCI5→RCI+HCI+B
3ROH+PCI3→3RCI+A
ROH+PCI5→RCI+HCI+B
- POCI3 and H3PO3
- POCI3 and H3PO4
- H3PO4 and POCI3
H3PO3 and POCI3
The Correct Option is D
Solution and Explanation
The given reactions involve the conversion of alcohols (ROH) to alkyl chlorides (RCl) using phosphorus chlorides (PCl3 and PCl5). Let's analyze each reaction to determine the products:
1. In the reaction 3ROH+PCl3→3RCl+A, the alcohols react with phosphorus trichloride (PCl3) to form alkyl chlorides (RCl) and a phosphorus-containing compound A as a byproduct. The balanced reaction is:
PCl3 + 3ROH → 3RCl + H3PO3
Thus, the product A is H3PO3 (phosphorous acid).
2. In the second reaction ROH+PCl5→RCl+HCl+B, the alcohol is converted to the alkyl chloride (RCl), and hydrogen chloride (HCl) is formed along with a phosphorus-containing compound B. Here, phosphorus pentachloride (PCl5) breaks down, and the balanced equation is:
PCl5 + ROH → RCl + HCl + POCl3
Thus, the product B is POCl3 (phosphoryl chloride).
Based on the analysis, the products A and B for each reaction are:
| Reaction | Product A | Product B |
|---|---|---|
| 3ROH+PCl3→3RCl+A | H3PO3 | - |
| ROH+PCl5→RCl+HCl+B | - | POCl3 |
The correct answer is: H3PO3 and POCl3.
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