The product of $\sqrt{2}$ and $(2-\sqrt{2})$ will be:
Step 1: Multiply the given terms
\[
\sqrt{2} \times (2-\sqrt{2}) = \sqrt{2} \times 2 - \sqrt{2} \times \sqrt{2}
\]
\[
= 2\sqrt{2} - 2
\]
Step 2: Classify the result
The expression $2\sqrt{2} - 2$ is the difference of an irrational number ($2\sqrt{2}$) and a rational number ($2$).
Thus, the result is irrational.
\[
\boxed{2\sqrt{2} - 2 \ \text{is irrational}}
\]
Match List-I with List-II and choose the correct option:
\[ \begin{array}{|l|l|} \hline \textbf{LIST-I (Function)} & \textbf{LIST-II (Expansion)} \\ \hline A. \log(1-x) & I. 1 + \frac{1}{3} + \frac{1}{6} + \frac{3}{40} + \frac{15}{336} + \dots \\ \hline B. \sin^{-1} x & II. 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \dots \\ \hline C. \log 2 & III. x + \frac{1}{2} \frac{x^3}{3} + \frac{1 \cdot 3}{2 \cdot 4} \frac{x^5}{5} + \frac{1 \cdot 3 \cdot 5}{2 \cdot 4 \cdot 6} \frac{x^7}{7} + \dots, -1 < x \le 1 \\ \hline D. \frac{\pi}{2} & IV. -x - \frac{x^2}{2} - \frac{x^3}{3} - \dots, -1 \le x < 1 \\ \hline \end{array} \]
The following table shows the ages of the patients admitted in a hospital during a year. Find the mode and the median of these data.
\[\begin{array}{|c|c|c|c|c|c|c|} \hline Age (in years) & 5-15 & 15-25 & 25-35 & 35-45 & 45-55 & 55-65 \\ \hline \text{Number of patients} & \text{6} & \text{11} & \text{21} & \text{23} & \text{14} & \text{5} \\ \hline \end{array}\]