Question:

The product of $\sqrt{2}$ and $(2-\sqrt{2})$ will be:
 

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Multiplying a surd (like $\sqrt{2}$) with a linear expression often produces an irrational result unless special cancellation occurs.
Updated On: Sep 6, 2025
  • An irrational number
  • A rational number
  • An integer
  • None of the above
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The Correct Option is A

Solution and Explanation


Step 1: Multiply the given terms
\[ \sqrt{2} \times (2-\sqrt{2}) = \sqrt{2} \times 2 - \sqrt{2} \times \sqrt{2} \] \[ = 2\sqrt{2} - 2 \]

Step 2: Classify the result
The expression $2\sqrt{2} - 2$ is the difference of an irrational number ($2\sqrt{2}$) and a rational number ($2$).
Thus, the result is irrational.
\[ \boxed{2\sqrt{2} - 2 \ \text{is irrational}} \]

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