Question:

Two swimmers, Ankit and Bipul, start swimming from the opposite ends of a swimming pool at the same time. Ankit can cover the length of the pool once in 10 minutes. Bipul can cover the length of the pool once in 15 minutes. They swim back and forth for 80 minutes without stopping. The number of times they meet each other is ________

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A quick formula for this type of problem is: Total time / Time between meetings (after the first). Let \(t_1\) and \(t_2\) be the times taken by each person. Time for 1st meeting = \( \frac{t_1 t_2}{t_1 + t_2} \). Time for subsequent meetings = \( \frac{2 t_1 t_2}{t_1 + t_2} \). Here, time for 1st meeting = 6 min, time for subsequent = 12 min. Number of meetings = 1 (for the first) + floor((80-6)/12) = 1 + floor(74/12) = 1 + 6 = 7.
Updated On: Oct 14, 2025
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This is a relative speed problem. When two objects move towards each other, their relative speed is the sum of their individual speeds. We can find the time taken for each meeting and count how many meetings occur within the given 80-minute timeframe.
Step 2: Key Formula or Approach:
1. Let the length of the pool be L. Calculate the speeds of Ankit (\(v_A\)) and Bipul (\(v_B\)). 2. For the first meeting, they collectively cover a distance of L. Time = Distance / Relative Speed. 3. For all subsequent meetings, they collectively cover a distance of 2L (since they each swim one length to return to their starting sides and then move towards each other again). 4. Calculate the times of each meeting and count how many fall within 80 minutes.
Step 3: Detailed Explanation:
Let the length of the pool be L units. Speed of Ankit, \( v_A = \frac{L}{10} \) units/minute. Speed of Bipul, \( v_B = \frac{L}{15} \) units/minute. They are swimming towards each other, so their relative speed is: \[ v_{rel} = v_A + v_B = \frac{L}{10} + \frac{L}{15} = \frac{3L + 2L}{30} = \frac{5L}{30} = \frac{L}{6} \text{ units/minute} \] First Meeting: To meet for the first time, they need to cover a total distance of L. \[ \text{Time for 1st meeting} = \frac{\text{Distance}}{\text{Relative Speed}} = \frac{L}{L/6} = 6 \text{ minutes} \] Subsequent Meetings: After the first meeting, for them to meet again, they must collectively swim a total distance of 2L. For example, Ankit swims to one end and turns back, while Bipul swims to the other end and turns back. \[ \text{Time between subsequent meetings} = \frac{2L}{L/6} = 12 \text{ minutes} \] Now, let's find the times at which the meetings occur:

1st meeting: 6 minutes
2nd meeting: 6 + 12 = 18 minutes
3rd meeting: 18 + 12 = 30 minutes
4th meeting: 30 + 12 = 42 minutes
5th meeting: 42 + 12 = 54 minutes
6th meeting: 54 + 12 = 66 minutes
7th meeting: 66 + 12 = 78 minutes
8th meeting: 78 + 12 = 90 minutes (This is after the 80-minute duration)
Since the 7th meeting occurs at 78 minutes, which is within the 80-minute timeframe, they meet a total of 7 times.
Step 4: Final Answer:
The number of times they meet each other is 7.
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