The product formed in the following reaction.
The Correct Option is B
Solution and Explanation
So, the correct option is (B).
Top Questions on Hydrocarbons
Complete the following reactions by writing the structure of the main products:
- CBSE CLASS XII - 2025
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- Complete the following reactions by writing the structural formulae of ‘A’ and ‘B’:
(i) CH$_3$CH=CH$_2$ + HBr $\xrightarrow{\text{Peroxide}}$ ‘A’ $\xrightarrow{KOH}$ ‘B’
(ii) CH$_3$CH$_2$CHCl + alc. KOH $\xrightarrow{\Delta}$ ‘A’ $\xrightarrow{\text{H}_2\text{O}}$ ‘B’ (Main product)- CBSE CLASS XII - 2025
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- A halide with formula C6H13Br gave two isomeric alkenes A and B on dehydrobromination. On ozonolysis of mixture of A and B the following compounds were obtained: CH3COCH3, CH3CHO, CH3CH2CHO and (CH3)2CHCHO. The halide is:
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- Which of the following is an alkene?
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- Double bond is present in:
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Questions Asked in JEE Main exam
- The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be ________________________ A.
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- Let \( M \) denote the set of all real matrices of order 3 x 3 and let \( S = \{-3, -2, -1, 1, 2\} \). Let
\( S_1 = \{A = [a_{ij}] \in M : A = A^T \text{ and } a_{ij} \in S, \forall i, j\} \),
\( S_2 = \{A = [a_{ij}] \in M : A = -A^T \text{ and } a_{ij} \in S, \forall i, j\} \),
\( S_3 = \{A = [a_{ij}] \in M : a_{11} + a_{22} + a_{33} = 0 \text{ and } a_{ij} \in S, \forall i, j\} \).
If \(n(S_1 \cup S_2 \cup S_3) = 125\), then \( \alpha \) equals:- JEE Main - 2025
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Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
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- Using the principal values of the inverse trigonometric functions the sum of the maximum and the minimum values of \(16((sec^{-1}x)^{2}+(cosec^{-1}x)^{2})\) is:
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- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
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JEE Main Notification
GMC Azamgarh Admission 2025: Dates, Courses, Fees, Eligibility, SelectJuly 22, 2025Concepts Used:
Hydrocarbons - Reaction Mechanism
Hydrocarbons are organic compounds that are entirely made up of only two kinds of atoms – carbon and hydrogen. Typically, hydrocarbons are colourless gases that have very weak odours.
Mechanism of electrophilic substitution reactions:
According to experimental evidences, SE (S = substitution; E = electrophilic) reactions are supposed to proceed via the following three steps:
- Generation of the electrophile
- Formation of carbocation intermediate
- Removal of proton from the carbocation interm