Question

The probability of getting a number 4 or 5 in throwing a die is

• A. \(\frac{1}{2}\)
• B. \(\frac{1}{3}\)
• C. \(\frac{1}{6}\)
• D. \(\frac{2}{3}\)

Hint:

This is another "or" probability problem with mutually exclusive events. P(4 or 5) = P(4) + P(5) = 1/6 + 1/6 = 2/6 = 1/3.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
This problem asks for the probability of getting one of two possible outcomes when a single standard six-sided die is thrown.

Step 2: Key Formula or Approach:
\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]

Step 3: Detailed Explanation:
When a single die is thrown, the total number of possible outcomes is 6. The sample space is \{1, 2, 3, 4, 5, 6\}.
The favorable outcomes are "getting a number 4 or 5".
The numbers in the sample space that satisfy this condition are 4 and 5.
The number of favorable outcomes is 2.
Now, calculate the probability:
\[ P(\text{4 or 5}) = \frac{2}{6} = \frac{1}{3} \]

Step 4: Final Answer:
The probability is \(\frac{1}{3}\).