The probability \( P \) of a 10-year flood (i.e., return period \( T = 10 \) years) occurring at least once in \( n = 4 \) years is given by:
\[
P = 1 - (1 - \frac{1}{T})^n
\]
\[
P = 1 - \left(1 - \frac{1}{10}\right)^4 = 1 - (0.9)^4 = 1 - 0.6561 = 0.3439
\]
\[
⇒ P \approx 34.39% \approx \boxed{35%}
\]
Thus, the probability is 35%.