Given:
Water supply = 15000 m$^3$/day = 15,000,000 liters/day
Chlorine dosage = 0.5 ppm = 0.5 mg/L
Chlorine required per day = 15,000,000 L $\times$ 0.5 mg/L = 7,500,000 mg = 7.5 kg
Note: 1 ppm = 1 mg/L
Since bleaching powder contains 25% available chlorine,
Required bleaching powder = $\frac{7.5}{0.25}$ = 30 kg/day