Step 1: Recall the relationship between the power of a lens and its focal length.
The power \( P \) of a lens in diopters (D) is the reciprocal of its focal length \( f \) in meters (m):
\[
P = \frac{1}{f}
\]
Step 2: Convert the given power to find the focal length in meters.
Given power \( P = 4 \, D \), we can find the focal length \( f \):
\[
4 = \frac{1}{f}
\]
\[
f = \frac{1}{4} \, m
\]
\[
f = 0.25 \, m
\]
Step 3: Convert the focal length from meters to centimeters.
Since \( 1 \, m = 100 \, cm \), we can convert the focal length:
\[
f = 0.25 \, m \times \frac{100 \, cm}{1 \, m}
\]
\[
f = 25 \, cm
\]
The focal length of the lens is \( 25 \, cm \).