Question

The points of intersection of three lines $2X + 3Y - 5 = 0$, $5X - 7Y + 2 = 0$ and $9X - 5Y - 4 = 0$

• A. form a triangle
• B. are on lines perpendicular to each other
• C. are on lines parallel to each other
• D. are coincident

Hint:

For line equations in $ax+by+c=0$ form, slope $m = -\frac{a}{b}$.

Answer 1

The Correct Option is A

Check if any two lines are parallel: Slopes are $-\frac{2}{3}$, $\frac{5}{7}$, and $\frac{9}{5}$ — all different, so all lines intersect pairwise at distinct points. This means the three lines form a triangle.