We are given that \( Q \) lies on the circle \( x^2 + y^2 = 9 \), and the point \( P \) divides the line segment \( QA \) in the ratio 1:2.
First, we determine the parametric equations for the coordinates of \( P \).
The coordinates of \( P \) that divides \( QA \) in the ratio \( 1:2 \) are given by the section formula: \[ P = \left( \frac{2x_1 + x_2}{3}, \frac{2y_1 + y_2}{3} \right), \] where \( A = (4, 4) \) and \( Q = (x_1, y_1) \) lies on the circle \( x^2 + y^2 = 9 \). So, \( P \) will trace a curve as \( Q \) moves along the circle. Since \( P \) divides \( QA \) in the ratio 1:2, the locus of \( P \) will be a circle with radius \( \frac{2}{3} \) of the radius of the original circle.
The radius of the circle traced by \( P \) is \( \frac{2}{3} \times 3 = 2 \).
Thus, the perimeter (circumference) of the locus of \( P \) is: \[ \text{Perimeter} = 2\pi \times 2 = 4\pi. \] Thus, the correct answer is \( 4\pi \).
If $$ f(x) = \begin{cases} \frac{6x^2 + 1}{4x^3 + 2x + 3}, & 0 < x < 1 \\ x^2 + 1, & 1 \leq x < 2 \end{cases} $$ then $$ \int_{0}^{2} f(x) \,dx = ? $$
Let $E_1$ and $E_2$ be two independent events of a random experiment such that
$P(E_1) = \frac{1}{2}, \quad P(E_1 \cup E_2) = \frac{2}{3}$.
Then match the items of List-I with the items of List-II:
The correct match is:
In the given circuit, the potential difference across the 5 \(\mu\)F capacitor is