The pair of molecules/ions with same geometry but central atoms in different states of hybridization is:
Show Hint
- Molecules with different hybridization can still have the same molecular geometry.
- \( SnCl_2, H_2O \)
- \( SF_4, XeF_4 \)
- \( NH_4^+, CO_3^{2-} \)
- \( PF_5, BrF_5 \)
The Correct Option is A
Solution and Explanation
We analyze the hybridization and geometry of the given molecules: 1. \( SnCl_2 \) (Tin(II) chloride) - Central atom: Sn - Hybridization: \( sp^2 \) (trigonal planar) - Lone pairs: 1 - Shape: Bent (V-shaped) 2. \( H_2O \) (Water) - Central atom: O - Hybridization: \( sp^3 \) (tetrahedral electronic geometry) - Lone pairs: 2 - Shape: Bent (V-shaped) 3. Comparison: - Both molecules have the same bent geometry, but their hybridization differs. - \( SnCl_2 \) → \( sp^2 \) - \( H_2O \) → \( sp^3 \) Thus, the correct answer is \(\boxed{SnCl_2, H_2O}\).
Top Questions on GROUP 14 ELEMENTS
Which one of the following complex ions has geometrical isomers?
Option 1: \(\left[\text{Co}(\text{Cl})_2(\text{en})_2\right]^+\)
Option 2: \(\left[\text{Cr}(\text{NH}_3)_4(\text{en})\right]^{3+}\)
Option 3: \(\left[\text{Co}(\text{en})_3\right]^{3+}\)
Option 4: \(\left[\text{Ni}(\text{NH}_3)_5\right]\text{Br}\)
- TS EAMCET - 2024
- Chemistry
- GROUP 14 ELEMENTS
Given are two statements regarding the properties of carbon in Group 14 of the periodic table:
Statement-I: Carbon has the highest catenation power in group 14 elements.
Statement-II: Carbon has small size and high electronegativity compared to other elements of group 14.- AP EAMCET - 2024
- Chemistry
- GROUP 14 ELEMENTS
- Identify the correct statements from the following: (i) Ti (IV) is more stable than Ti (III) and Ti (II)
(ii) Among 3d-series elements (from Z = 22 to 29) only copper has positive reduction potential (\( M^{2+}/M \)) (iii) Both Sc and Zn exhibit +1 oxidation state- TS EAMCET - 2024
- Chemistry
- GROUP 14 ELEMENTS
- Identify the pair in which the difference in bond order value is maximum.
- TS EAMCET - 2024
- Chemistry
- GROUP 14 ELEMENTS
- Evaluate the following statements related to group 14 elements for their correctness.
(A) Covalent radius decreases down the group from C to Pb in a regular manner.
(B) Electronegativity decreases from C to Pb down the group gradually.
(C) Maximum covalence of C is 4 whereas other elements can expand their covalence due to presence of d orbitals.
(D) Heavier elements do not form ppi-ppi bonds.
(E) Carbon can exhibit negative oxidation states.
Choose the correct answer from the options given below:- JEE Main - 2024
- Chemistry
- GROUP 14 ELEMENTS
Questions Asked in TS EAMCET exam
Find \( \frac{dy}{dx} \) for the given function:
\[ y = \tan^{-1} \left( \frac{\sin^3(2x) - 3x^2 \sin(2x)}{3x \sin(2x) - x^3} \right). \]
- TS EAMCET - 2024
- Fundamental Theorem of Calculus
- For a given function \( y = f(x) \), \( \delta y \) denotes the actual error in \( y \) corresponding to actual error \( \delta x \) in \( x \) and \( dy \) denotes the approximate value of \( \delta y \). If \( y = f(x) = 2x^2 - 3x + 4 \) and \( \delta x = 0.02 \), then the value of \( \delta y - dy \) when \( x = 5 \) is: \vspace{0.5cm}
- TS EAMCET - 2024
- Fundamental Theorem of Calculus
The length of the normal drawn at \( t = \frac{\pi}{4} \) on the curve \( x = 2(\cos 2t + t \sin 2t) \), \( y = 4(\sin 2t + t \cos 2t) \) is:
- TS EAMCET - 2024
- Coordinate Geometry
If water is poured into a cylindrical tank of radius 3.5 ft at the rate of 1 cubic ft/min, then the rate at which the level of the water in the tank increases (in ft/min) is:
- TS EAMCET - 2024
- Kinematics
The function \( y = 2x^3 - 8x^2 + 10x - 4 \) is defined on \([1,2]\). If the tangent drawn at a point \( (a,b) \) on the graph of this function is parallel to the X-axis and \( a \in (1,2) \), then \( a = \) ?
- TS EAMCET - 2024
- Fundamental Theorem of Calculus