Consider the oxides of group 14 elements \(SiO_2,GeO_2,SnO_2,PbO_2,CO\) and \(GeO\). The amphoteric oxides are
- \(GeO, GeO_2\)
- \(SiO_2, GeO_2\)
- \(SnO_2, PbO_2\)
- \(SnO_2, CO\)
The Correct Option is C
Solution and Explanation
\(SnO_2\) and \(PbO_2\) are amphoteric.
Top Questions on GROUP 14 ELEMENTS
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Statement II: Group 14 contains non-metallic, metallic, as well as metalloid elements.
In the light of the above statements, choose the most appropriate from the options given below:- JEE Main - 2024
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(C) Maximum covalence of C is 4 whereas other elements can expand their covalence due to presence of d orbitals.
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(E) Carbon can exhibit negative oxidation states.
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Option 1: \(\left[\text{Co}(\text{Cl})_2(\text{en})_2\right]^+\)
Option 2: \(\left[\text{Cr}(\text{NH}_3)_4(\text{en})\right]^{3+}\)
Option 3: \(\left[\text{Co}(\text{en})_3\right]^{3+}\)
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Given are two statements regarding the properties of carbon in Group 14 of the periodic table:
Statement-I: Carbon has the highest catenation power in group 14 elements.
Statement-II: Carbon has small size and high electronegativity compared to other elements of group 14.- AP EAMCET - 2024
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