Consider the oxides of group 14 elements \(SiO_2,GeO_2,SnO_2,PbO_2,CO\) and \(GeO\). The amphoteric oxides are
- \(GeO, GeO_2\)
- \(SiO_2, GeO_2\)
- \(SnO_2, PbO_2\)
- \(SnO_2, CO\)
The Correct Option is C
Solution and Explanation
\(SnO_2\) and \(PbO_2\) are amphoteric.
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Option 2: \(\left[\text{Cr}(\text{NH}_3)_4(\text{en})\right]^{3+}\)
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