Let's evaluate each of the given statements related to group 14 elements:
Based on the evaluation:
Hence, the correct set of statements is (C), (D), and (E) Only.
The correct answer is:
(A) Down the group, radius increases.
(B) EN does not decrease gradually from C to Pb.
(C) Correct.
(D) Correct.
(E) Range of oxidation state of carbon: \(-4\) to \(+4\).
Thus the correct answer is Option 1.
Which one of the following complex ions has geometrical isomers?
Option 1: \(\left[\text{Co}(\text{Cl})_2(\text{en})_2\right]^+\)
Option 2: \(\left[\text{Cr}(\text{NH}_3)_4(\text{en})\right]^{3+}\)
Option 3: \(\left[\text{Co}(\text{en})_3\right]^{3+}\)
Option 4: \(\left[\text{Ni}(\text{NH}_3)_5\right]\text{Br}\)
Given are two statements regarding the properties of carbon in Group 14 of the periodic table:
Statement-I: Carbon has the highest catenation power in group 14 elements.
Statement-II: Carbon has small size and high electronegativity compared to other elements of group 14.


For the circuit shown above, the equivalent gate is:
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is: