
The question involves evaluating the relative stability of resonance structures. The stability of resonance structures mainly depends on the following factors:
Analyzing the given resonance structures:
Based on the above analysis, the order of relative stability is:
\(I > II > III\)
Structure I is the most stable because it is a neutral resonating structure. In general, neutral structures are more stable compared to charged structures.
Structure II is less stable than I because it involves a positive charge on a less electronegative atom compared to structure III. However, it is more stable than III because the negative charge in III is on a carbon atom, making it the least stable due to charge separation.
Structure III is the least stable among the three due to the presence of a negative charge on carbon and overall charge separation, making it highly unstable.
The Correct answer is: \(I >II >III\)
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are : 
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is : 

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 