Question:

The number of zinc ions present in the molecular formula of Q Q is:

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Consider both stoichiometric possibilities for product formation.
Updated On: Jan 20, 2025
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Solution and Explanation

Step 1: Analyze the reaction pathways. K4[Fe(CN)6]+3ZnCl2K2Zn3[Fe(CN)6]2+6KCl K_4[Fe(CN)_6] + 3ZnCl_2 \rightarrow K_2Zn_3[Fe(CN)_6]_2 + 6KCl This gives 3 zinc ions. Alternatively: K4[Fe(CN)6]+2ZnCl2Zn2[Fe(CN)6]+4KCl K_4[Fe(CN)_6] + 2ZnCl_2 \rightarrow Zn_2[Fe(CN)_6] + 4KCl This gives 2 zinc ions.
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