Among the following options, select the option in which each complex in
Set-I shows geometrical isomerism and the two complexes in
Set-II are ionization isomers of each other.
[en = H2NCH2CH2NH2]
Set-I Analysis:
Set-II Analysis:
\([Co(NH_3)_5Cl]SO_4\) and \([Co(NH_3)_5(SO_4)]Cl\): These two complexes are ionization isomers because they differ in the ion released in solution.
Conclusion:
Option (C) satisfies both conditions:
To solve the problem, we analyze both sets to find complexes showing geometrical isomerism in Set-I and ionization isomers in Set-II.
1. Geometrical Isomerism in Set-I:
- [Co(NH3)3(NO2)3] does not show geometrical isomerism as it contains identical ligands.
- [Co(en)2Cl2] contains two bidentate ethylenediamine (en) ligands and two chloride ligands; it exhibits cis and trans geometrical isomers.
Hence, these two complexes are suitable for geometrical isomerism.
2. Ionization Isomers in Set-II:
- [Co(NH3)5Cl]SO4 and [Co(NH3)5(SO4)]Cl differ by interchange of ligands inside and outside coordination sphere, so they are ionization isomers.
Final Answer:
Set-I: [Co(NH3)3(NO2)3] and [Co(en)2Cl2]
Set-II: [Co(NH3)5Cl]SO4 and [Co(NH3)5(SO4)]Cl
This matches option C.
List-I (Complex) | List-II (Isomerism) |
---|---|
A) [Co(NH3)5Br]SO4 | V) Ionization |
B) [Co(en)3]3+ | I) Optical |
C) [Co(NH3)5(NO2)]2+ | II) Linkage |
D) [Co(NH3)3Cl3] | III) Geometrical |
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct: