Among the following options, select the option in which each complex in
Set-I shows geometrical isomerism and the two complexes in
Set-II are ionization isomers of each other.
[en = H2NCH2CH2NH2]
Among the following options, select the option in which each complex in
Set-I shows geometrical isomerism and the two complexes in
Set-II are ionization isomers of each other.
[en = H2NCH2CH2NH2]
- Set-I: [Ni(CO)4] and [PdCl2(PPh3)2]
Set-II: [Co(NH3)5CI]SO4 and [Co(NH3)5(SO4)]Cl - Set-I: [Co(en) (NH3)2Cl2] and [PdCl2(PPh3)2]
Set-II: [Co(NH3)6] [Cr(CN)6] and [Cr(NH3)6][Co(CN)6] - Set-I: [Co(NH3)3(NO2)3] and [Co(en)2Cl2]
Set-II: [Co(NH3)5CI]SO4 and [Co(NH3)5(SO4)]Cl - Set-I: [Cr(NH3)5CI]Cl2 and [Co(en) (NH3)2Cl2]
Set-II: [Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]Cl2H2O
The Correct Option is C
Approach Solution - 1
Set-I Analysis:
- \([Co(NH_3)_3(NO_2)_3]\): This complex is of type \([Mab_3]\), which can exhibit geometrical isomerism with facial (fac) and meridional (mer) isomers.
- \([Co(en)_2Cl_2]\): This complex is of type \([M(AA)_2a_2]\), where (en) is a bidentate ligand, and it shows cis and trans isomerism.
Set-II Analysis:
\([Co(NH_3)_5Cl]SO_4\) and \([Co(NH_3)_5(SO_4)]Cl\): These two complexes are ionization isomers because they differ in the ion released in solution.
- One releases \( Cl^- \).
- The other releases \( SO_4^{2-} \).
Conclusion:
Option (C) satisfies both conditions:
- Geometrical isomerism in Set-I.
- Ionization isomerism in Set-II.
Approach Solution -2
To solve the problem, we analyze both sets to find complexes showing geometrical isomerism in Set-I and ionization isomers in Set-II.
1. Geometrical Isomerism in Set-I:
- [Co(NH3)3(NO2)3] does not show geometrical isomerism as it contains identical ligands.
- [Co(en)2Cl2] contains two bidentate ethylenediamine (en) ligands and two chloride ligands; it exhibits cis and trans geometrical isomers.
Hence, these two complexes are suitable for geometrical isomerism.
2. Ionization Isomers in Set-II:
- [Co(NH3)5Cl]SO4 and [Co(NH3)5(SO4)]Cl differ by interchange of ligands inside and outside coordination sphere, so they are ionization isomers.
Final Answer:
Set-I: [Co(NH3)3(NO2)3] and [Co(en)2Cl2]
Set-II: [Co(NH3)5Cl]SO4 and [Co(NH3)5(SO4)]Cl
This matches option C.
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