First we arrange 5 red cubes in a row and assume x1, x2, x3, x4, x5 and x6 number of blue cubes between them
Here we see,
x1 + x2 + x3 + x4 + x5 + x6 = 11
also,
x2, x3, x4, x5 ≥ 2
Hence,
x1 + x2 + x3 + x4 + x5 + x6 = 3
Therefore ,
Number of solutions found = 8C5
= 56
The value of 49C3 + 48C3 + 47C3 + 46C3 + 45C3 + 45C4 is:
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.
The method of forming subsets by selecting data from a larger set in a way that the selection order does not matter is called the combination.
But you are only allowed to pick three.
It is used for a group of data (where the order of data doesn’t matter).