The number of students who take both the subjects mathematics and chemistry is 30. This represents 10% of the enrolment in mathematics and 12% of the enrolment in chemistry. How many students take at least one of these two subjects?
Show Hint
To find the number of students taking at least one subject, use the formula:
\[
|A \cup B| = |A| + |B| - |A \cap B|
\]
where \( A \) and \( B \) are the two subjects.
Let the number of students who take only Mathematics be \( x \), and the number of students who take only Chemistry be \( y \).
From the Venn diagram:
- The total number of students in Mathematics is \( x + 30 \).
- The total number of students in Chemistry is \( y + 30 \).
Given conditions:
\[
30 = \frac{10}{100} (x + 30)
\]
Solving for \( x \):
\[
x + 30 = \frac{30 \times 100}{10} = 300
\]
\[
x = 270
\]
Similarly, for Chemistry:
\[
30 = \frac{12}{100} (y + 30)
\]
Solving for \( y \):
\[
y + 30 = \frac{30 \times 100}{12} = 250
\]
\[
y = 220
\]
Now, using the formula for the union of two sets:
\[
|M \cup C| = |M| + |C| - |M \cap C|
\]
Substituting values:
\[
x + y + 30 = 270 + 220 + 30 = 520
\]
Thus, the final answer is:
\[
\boxed{520}
\]