Digits are 1,2,2,2,3,3,5
If unit digit 5 , then total numbers \(=\frac{6!}{3!2!}=60\)
If unit digit 3 , then total numbers \(=\frac{6!}{3!} =120\)
If unit digit 1 , then total numbers \(=\frac{6!}{3!2!}=60\)
∴ total numbers =60+60+120=240
So , the correct answer is 240
Number of 4-digit numbers that are less than or equal to 2800 and either divisible by 3 or by 11 , is equal to
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.
Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.