To determine the number of radial nodes in a 3p orbital, we need to understand the concept of radial nodes and how they are calculated for atomic orbitals.
Understanding Radial Nodes:
Radial nodes are regions where the probability of finding an electron is zero. They can be calculated using the formula:
\(N_{\text{radial}} = n - \ell - 1\)
where:
For a 3p orbital:
Substituting these values into the formula gives:
\(N_{\text{radial}} = 3 - 1 - 1 = 1\)
Thus, the number of radial nodes in a 3p orbital is 1.
Conclusion:
The correct answer is 1, which is consistent with the calculation based on quantum numbers. The remaining options (4, 2, 3) are incorrect because they do not align with the formula for radial nodes.
The number of radial nodes for an orbital is given by the formula:
Number of radial nodes = n − l − 1
where: - n is the principal quantum number. - l is the azimuthal quantum number
(orbital angular momentum quantum number).
For a 3p orbital: - n = 3 - l = 1 (since it is a p-orbital)
Applying the formula:
Number of radial nodes = 3 − 1 − 1 = 1
Conclusion: The number of radial nodes for the 3p orbital is 1.
Which of the following is the correct electronic configuration for \( \text{Oxygen (O)} \)?
Which of the following is/are correct with respect to the energy of atomic orbitals of a hydrogen atom?
(A) \( 1s<2s<2p<3d<4s \)
(B) \( 1s<2s = 2p<3s = 3p \)
(C) \( 1s<2s<2p<3s<3p \)
(D) \( 1s<2s<4s<3d \)
Choose the correct answer from the options given below:
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: